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How do i find the slope and the y- intercept of the regression line? (10 PTS!!!)?
mean is (x) 853.7 (y)244.33
st. dev is (x)497.8 (y)56.37
R is .694
you dnt have to give me the answers just the equation or setup...
i also have a ti-84 silver edition
(mean of x) = Σ x / n
Σ x = (mean of x) * n
similarly,
Σ y = (mean of y) * n
variance of x = (st dev of x)^2
variance of y = (st dev of y)^2
R^2 = (covariance of xy)^2 / (variance of x)(variance of y)
then
covariance of xy = Σ xy - (Σx * Σy)/n
The regression line is:
y = mx + b
m = [Σ xy - ((Σ x * Σ y) / n)] / (variance of x)
b = (mean of y) - m* (mean of x)
Thus you need to solve for
Σ xy
Σ x
Σ y
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