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Math Problem! HELP please!!!?
A migrating elephant herd started moving at a rate of 6 miles per hour. One elephant stood still and was left behind. Then this stray elephant sensed danger and began running at a rate of 10 miles per hour to reach the herd. The stray caught up in 5 minutes.
1. How long (in hours) did the stray run to catch up? How far did it run?
2. Find the distance the herd traveled while the stray ran to catch up. Then write an expression for the total distance the herd traveled. Let x represent the distance (in miles) that the herd traveled while the stray elephant stood still.
3. Use the distance you found in 1 and 2. Write and solve an equation to find out how far the herd traveled while the stray elephant stood still.
4. Make a table or graph to check your answer.
( The problem is found in "Algebra 1" Equations, Graphs, Applications, page 164, wrote by Ron Larson, Laurie Boswell, Timothy D. Kanold, and Lee Stiff."
1. 5 minutes * (1 hour/60 minutes) = 1/12 hour;
d = v*t d = (10 miles/hour)*(1/12 hour) = 10/12 miles = 5/6 miles
2. They traveled the same distance, so it must have also been 5/6 miles.
x = 6*t where t is the time the stray stood still
3. 5/6 = 6*(t+1/12)
again, distance traveled while stray stood still is x = 6*t
Solving this equation gives t=1/18 hour
x = 6*(1/18) = 1/3 mile
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